Combines Math problem for group

I just want to know what the prize is for the right answer.

Exactly- the population doesn't matter when you look at that because 34,000 plants per acre doesn't matter weither they are 20" or 30" apart. We plant our corn at around 24,000 pop. on 20", that comes out to being aprox. 1 plant every 12" in the row.

A cookie!!!

Hey Nod, You just got to get yourself a demo in a lexion 590,you'll be blown away by its capacity compared to the 470R!!!

That was the whole point. I don't think plant population is relevant to this example, but I conclude that 18 rows at 30" apart is gonna give you a header 1.5 times as wide as 18 rows at 20". This entails that if you harvest at the same speed with both, the 30" spacing is gonna do 1.5 times the area in the same time. At a constant yield, it should therefore harvest 1.5 times as much grain, since I'm working with the area harvested and not the number of stalks.

Ok then, I'll dust off the ol' calculator and get right on it.

Are you Al GoreIJIJ!!

very good question but what about if you use a 6 row instead and travel 5.5IJ I figured since you guys already got those calculators warmed up you could answer this old guys problem. thanks

6 rows at 30inches = 180 inches = 15 feet (Thanks, Ed B): 5280 feet (in a mile)x 15 x 5.5mph = 435600 sq ft_ hr 435600 sq ft _ hr = 10 a_hr @ yield of 200=2000 bu _ hr 2000 _ 60 = 33.3 bu _ min Unloading 1000 bu = 5.5 minutes @ 33.3 bu _ min = 183.3 bu in 5.5 min Thus you need 1000-183.3 bu tank = 816.7 bushel tank. And maybe some extra wheels.

I don't get it....you take 3.69 minutes to unload the first 665, rightIJ In which time you harvest the remaining 335.42, rightIJ So what about unloading this and the stuff that's harvested as you do thisIJ Or is my brain just shutting down from too much mathIJ Aargh! the PAIN......